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136046444551 = 201167651141
BaseRepresentation
bin111111010110100000…
…0000000000000000111
3111000011022101110020121
41332231000000000013
54212110342211201
6142255431242411
712554233461403
oct1765500000007
9430138343217
10136046444551
1152773742446
1222449819407
13caa1782584
146828528103
153813ac29a1
hex1fad000007

136046444551 has 4 divisors (see below), whose sum is σ = 136114097704. Its totient is φ = 135978791400.

The previous prime is 136046444549. The next prime is 136046444609. The reversal of 136046444551 is 155444640631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136046444551 - 21 = 136046444549 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136046444498 and 136046444507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136046444351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33823560 + ... + 33827581.

It is an arithmetic number, because the mean of its divisors is an integer number (34028524426).

Almost surely, 2136046444551 is an apocalyptic number.

136046444551 is a deficient number, since it is larger than the sum of its proper divisors (67653153).

136046444551 is an equidigital number, since it uses as much as digits as its factorization.

136046444551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67653152.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 136046444551 in words is "one hundred thirty-six billion, forty-six million, four hundred forty-four thousand, five hundred fifty-one".

Divisors: 1 2011 67651141 136046444551