Base | Representation |
---|---|
bin | 10000001101111… |
… | …11000100000101 |
3 | 100111000000000012 |
4 | 20012333010011 |
5 | 234312031101 |
6 | 21300000005 |
7 | 3241253012 |
oct | 1006770405 |
9 | 314000005 |
10 | 136048901 |
11 | 6a88360a |
12 | 39690005 |
13 | 22255b11 |
14 | 140d6709 |
15 | be25bbb |
hex | 81bf105 |
136048901 has 2 divisors, whose sum is σ = 136048902. Its totient is φ = 136048900.
The previous prime is 136048817. The next prime is 136048931. The reversal of 136048901 is 109840631.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71808676 + 64240225 = 8474^2 + 8015^2 .
It is a cyclic number.
It is not a de Polignac number, because 136048901 - 214 = 136032517 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136048931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68024450 + 68024451.
It is an arithmetic number, because the mean of its divisors is an integer number (68024451).
Almost surely, 2136048901 is an apocalyptic number.
It is an amenable number.
136048901 is a deficient number, since it is larger than the sum of its proper divisors (1).
136048901 is an equidigital number, since it uses as much as digits as its factorization.
136048901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 32.
The square root of 136048901 is about 11664.0002143347. Note that the first 3 decimals coincide. The cubic root of 136048901 is about 514.3179471383.
The spelling of 136048901 in words is "one hundred thirty-six million, forty-eight thousand, nine hundred one".
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