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136088409341 is a prime number
BaseRepresentation
bin111111010111110000…
…0000101010011111101
3111000021020100111010002
41332233200011103331
54212202113044331
6142303530524045
712555253251623
oct1765740052375
9430236314102
10136088409341
11527953a5195
122245b896625
13caaa386501
14682dd2d513
1538176119cb
hex1faf8054fd

136088409341 has 2 divisors, whose sum is σ = 136088409342. Its totient is φ = 136088409340.

The previous prime is 136088409323. The next prime is 136088409343. The reversal of 136088409341 is 143904880631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133217700100 + 2870709241 = 364990^2 + 53579^2 .

It is a cyclic number.

It is not a de Polignac number, because 136088409341 - 210 = 136088408317 is a prime.

Together with 136088409343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136088409343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68044204670 + 68044204671.

It is an arithmetic number, because the mean of its divisors is an integer number (68044204671).

Almost surely, 2136088409341 is an apocalyptic number.

It is an amenable number.

136088409341 is a deficient number, since it is larger than the sum of its proper divisors (1).

136088409341 is an equidigital number, since it uses as much as digits as its factorization.

136088409341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 497664, while the sum is 47.

The spelling of 136088409341 in words is "one hundred thirty-six billion, eighty-eight million, four hundred nine thousand, three hundred forty-one".