13611302040225 has 48 divisors (see below), whose sum is σ = 22614546951360. Its totient is φ = 7223718835200.

The previous prime is 13611302040199. The next prime is 13611302040241. The reversal of 13611302040225 is 52204020311631.

It is not a de Polignac number, because 13611302040225 - 2⁷ = 13611302040097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13611302040192 and 13611302040201.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 96287797 + ... + 96429053.

It is an arithmetic number, because the mean of its divisors is an integer number (471136394820).

Almost surely, 2^{13611302040225} is an apocalyptic number.

13611302040225 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

13611302040225 is a deficient number, since it is larger than the sum of its proper divisors (9003244911135).

13611302040225 is a wasteful number, since it uses less digits than its factorization.

13611302040225 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147570 (or 147565 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 13611302040225 its reverse (52204020311631), we get a palindrome (65815322351856).

The spelling of 13611302040225 in words is "thirteen trillion, six hundred eleven billion, three hundred two million, forty thousand, two hundred twenty-five".