Base | Representation |
---|---|
bin | 10011110011101101111… |
… | …100011101100010000110 |
3 | 11211010111111011201111201 |
4 | 103303231330131202012 |
5 | 134300220114342314 |
6 | 2521154420453114 |
7 | 200225563450336 |
oct | 23635574354206 |
9 | 4733444151451 |
10 | 1361201715334 |
11 | 48531197781a |
12 | 19b98784a19a |
13 | 9b48c7c9796 |
14 | 49c4d8970c6 |
15 | 2561be01b74 |
hex | 13cedf1d886 |
1361201715334 has 4 divisors (see below), whose sum is σ = 2041802573004. Its totient is φ = 680600857666.
The previous prime is 1361201715323. The next prime is 1361201715373. The reversal of 1361201715334 is 4335171021631.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1361201715293 and 1361201715302.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340300428832 + ... + 340300428835.
It is an arithmetic number, because the mean of its divisors is an integer number (510450643251).
Almost surely, 21361201715334 is an apocalyptic number.
1361201715334 is a deficient number, since it is larger than the sum of its proper divisors (680600857670).
1361201715334 is an equidigital number, since it uses as much as digits as its factorization.
1361201715334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 680600857669.
The product of its (nonzero) digits is 45360, while the sum is 37.
Adding to 1361201715334 its reverse (4335171021631), we get a palindrome (5696372736965).
The spelling of 1361201715334 in words is "one trillion, three hundred sixty-one billion, two hundred one million, seven hundred fifteen thousand, three hundred thirty-four".
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