Search a number
-
+
1361201715334 = 2680600857667
BaseRepresentation
bin10011110011101101111…
…100011101100010000110
311211010111111011201111201
4103303231330131202012
5134300220114342314
62521154420453114
7200225563450336
oct23635574354206
94733444151451
101361201715334
1148531197781a
1219b98784a19a
139b48c7c9796
1449c4d8970c6
152561be01b74
hex13cedf1d886

1361201715334 has 4 divisors (see below), whose sum is σ = 2041802573004. Its totient is φ = 680600857666.

The previous prime is 1361201715323. The next prime is 1361201715373. The reversal of 1361201715334 is 4335171021631.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1361201715293 and 1361201715302.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340300428832 + ... + 340300428835.

It is an arithmetic number, because the mean of its divisors is an integer number (510450643251).

Almost surely, 21361201715334 is an apocalyptic number.

1361201715334 is a deficient number, since it is larger than the sum of its proper divisors (680600857670).

1361201715334 is an equidigital number, since it uses as much as digits as its factorization.

1361201715334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 680600857669.

The product of its (nonzero) digits is 45360, while the sum is 37.

Adding to 1361201715334 its reverse (4335171021631), we get a palindrome (5696372736965).

The spelling of 1361201715334 in words is "one trillion, three hundred sixty-one billion, two hundred one million, seven hundred fifteen thousand, three hundred thirty-four".

Divisors: 1 2 680600857667 1361201715334