Base | Representation |
---|---|
bin | 10011110011101110001… |
… | …101010010101000001011 |
3 | 11211010111210110212100000 |
4 | 103303232031102220023 |
5 | 134300222232031430 |
6 | 2521155055214043 |
7 | 200225646113562 |
oct | 23635615225013 |
9 | 4733453425300 |
10 | 1361206127115 |
11 | 48531441041a |
12 | 19b989217323 |
13 | 9b4906b28c3 |
14 | 49c502c4bd9 |
15 | 2561c4c3e60 |
hex | 13cee352a0b |
1361206127115 has 24 divisors (see below), whose sum is σ = 2446810028208. Its totient is φ = 725976600480.
The previous prime is 1361206127107. The next prime is 1361206127137. The reversal of 1361206127115 is 5117216021631.
1361206127115 is a `hidden beast` number, since 1 + 3 + 6 + 1 + 20 + 612 + 7 + 1 + 15 = 666.
It is not a de Polignac number, because 1361206127115 - 23 = 1361206127107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1361206127115.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 560165916 + ... + 560168345.
It is an arithmetic number, because the mean of its divisors is an integer number (101950417842).
Almost surely, 21361206127115 is an apocalyptic number.
1361206127115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1361206127115 is a deficient number, since it is larger than the sum of its proper divisors (1085603901093).
1361206127115 is an equidigital number, since it uses as much as digits as its factorization.
1361206127115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1120334281 (or 1120334269 counting only the distinct ones).
The product of its (nonzero) digits is 15120, while the sum is 36.
The spelling of 1361206127115 in words is "one trillion, three hundred sixty-one billion, two hundred six million, one hundred twenty-seven thousand, one hundred fifteen".
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