Base | Representation |
---|---|
bin | 10011110011110000110… |
… | …100101111110010011001 |
3 | 11211010121212002002100211 |
4 | 103303300310233302121 |
5 | 134300320001241401 |
6 | 2521203304131121 |
7 | 200230021203565 |
oct | 23636064576231 |
9 | 4733555062324 |
10 | 1361250024601 |
11 | 485337173235 |
12 | 19b99ba66aa1 |
13 | 9b49981244c |
14 | 49c560706a5 |
15 | 25621295951 |
hex | 13cf0d2fc99 |
1361250024601 has 2 divisors, whose sum is σ = 1361250024602. Its totient is φ = 1361250024600.
The previous prime is 1361250024587. The next prime is 1361250024613. The reversal of 1361250024601 is 1064200521631.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1228007504025 + 133242520576 = 1108155^2 + 365024^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1361250024601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1361250025601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680625012300 + 680625012301.
It is an arithmetic number, because the mean of its divisors is an integer number (680625012301).
Almost surely, 21361250024601 is an apocalyptic number.
It is an amenable number.
1361250024601 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361250024601 is an equidigital number, since it uses as much as digits as its factorization.
1361250024601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 1361250024601 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, twenty-four thousand, six hundred one".
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