1361250637541 has 4 divisors (see below), whose sum is σ = 1361253148032. Its totient is φ = 1361248127052.

The previous prime is 1361250637499. The next prime is 1361250637679. The reversal of 1361250637541 is 1457360521631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1361250637541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1361250637492 and 1361250637501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1361250637441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66911 + ... + 1651356.

It is an arithmetic number, because the mean of its divisors is an integer number (340313287008).

Almost surely, 2^{1361250637541} is an apocalyptic number.

It is an amenable number.

1361250637541 is a deficient number, since it is larger than the sum of its proper divisors (2510491).

1361250637541 is an equidigital number, since it uses as much as digits as its factorization.

1361250637541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2510490.

The product of its (nonzero) digits is 453600, while the sum is 44.

The spelling of 1361250637541 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, six hundred thirty-seven thousand, five hundred forty-one".