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1361325717133 is a prime number
BaseRepresentation
bin10011110011110101010…
…101011111011010001101
311211010211010111122222221
4103303311111133122031
5134300443340422013
62521215010335341
7200231630446534
oct23636525373215
94733733448887
101361325717133
11485375972148
1219ba0128a551
139b4ac3c5025
1449c6213531b
1525627c4808d
hex13cf555f68d

1361325717133 has 2 divisors, whose sum is σ = 1361325717134. Its totient is φ = 1361325717132.

The previous prime is 1361325717121. The next prime is 1361325717139. The reversal of 1361325717133 is 3317175231631.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 897418971684 + 463906745449 = 947322^2 + 681107^2 .

It is an emirp because it is prime and its reverse (3317175231631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1361325717133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1361325717133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1361325717139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680662858566 + 680662858567.

It is an arithmetic number, because the mean of its divisors is an integer number (680662858567).

Almost surely, 21361325717133 is an apocalyptic number.

It is an amenable number.

1361325717133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1361325717133 is an equidigital number, since it uses as much as digits as its factorization.

1361325717133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 238140, while the sum is 43.

The spelling of 1361325717133 in words is "one trillion, three hundred sixty-one billion, three hundred twenty-five million, seven hundred seventeen thousand, one hundred thirty-three".