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1361364120050 = 2521123839713367
BaseRepresentation
bin10011110011110111100…
…111111111000111110010
311211010220210202201220012
4103303313213333013302
5134301033203320200
62521222501414522
7200232605043434
oct23636747770762
94733823681805
101361364120050
114853956118a0
1219ba1210a442
139b4b734c94c
1449c67290654
152562b2d1a35
hex13cf79ff1f2

1361364120050 has 192 divisors, whose sum is σ = 2947455350784. Its totient is φ = 462955468800.

The previous prime is 1361364120049. The next prime is 1361364120101. The reversal of 1361364120050 is 500214631631.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1361364119989 and 1361364120016.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 101838467 + ... + 101851833.

It is an arithmetic number, because the mean of its divisors is an integer number (15351329952).

Almost surely, 21361364120050 is an apocalyptic number.

1361364120050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1361364120050 is an abundant number, since it is smaller than the sum of its proper divisors (1586091230734).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1361364120050 is a wasteful number, since it uses less digits than its factorization.

1361364120050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13593 (or 13588 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 1361364120050 its reverse (500214631631), we get a palindrome (1861578751681).

The spelling of 1361364120050 in words is "one trillion, three hundred sixty-one billion, three hundred sixty-four million, one hundred twenty thousand, fifty".