Base | Representation |
---|---|
bin | 10011110011110111100… |
… | …111111111000111110010 |
3 | 11211010220210202201220012 |
4 | 103303313213333013302 |
5 | 134301033203320200 |
6 | 2521222501414522 |
7 | 200232605043434 |
oct | 23636747770762 |
9 | 4733823681805 |
10 | 1361364120050 |
11 | 4853956118a0 |
12 | 19ba1210a442 |
13 | 9b4b734c94c |
14 | 49c67290654 |
15 | 2562b2d1a35 |
hex | 13cf79ff1f2 |
1361364120050 has 192 divisors, whose sum is σ = 2947455350784. Its totient is φ = 462955468800.
The previous prime is 1361364120049. The next prime is 1361364120101. The reversal of 1361364120050 is 500214631631.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1361364119989 and 1361364120016.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 101838467 + ... + 101851833.
It is an arithmetic number, because the mean of its divisors is an integer number (15351329952).
Almost surely, 21361364120050 is an apocalyptic number.
1361364120050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1361364120050 is an abundant number, since it is smaller than the sum of its proper divisors (1586091230734).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1361364120050 is a wasteful number, since it uses less digits than its factorization.
1361364120050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13593 (or 13588 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 1361364120050 its reverse (500214631631), we get a palindrome (1861578751681).
The spelling of 1361364120050 in words is "one trillion, three hundred sixty-one billion, three hundred sixty-four million, one hundred twenty thousand, fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •