1362114053311 has 4 divisors (see below), whose sum is σ = 1485942603624. Its totient is φ = 1238285503000.

The previous prime is 1362114053257. The next prime is 1362114053317. The reversal of 1362114053311 is 1133504112631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1362114053311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1362114053317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61914275140 + ... + 61914275161.

It is an arithmetic number, because the mean of its divisors is an integer number (371485650906).

Almost surely, 2^{1362114053311} is an apocalyptic number.

1362114053311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1362114053311 is a deficient number, since it is larger than the sum of its proper divisors (123828550313).

1362114053311 is a wasteful number, since it uses less digits than its factorization.

1362114053311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123828550312.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 1362114053311 its reverse (1133504112631), we get a palindrome (2495618165942).

The spelling of 1362114053311 in words is "one trillion, three hundred sixty-two billion, one hundred fourteen million, fifty-three thousand, three hundred eleven".