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1363140550147 is a prime number
BaseRepresentation
bin10011110101100001100…
…000100001111000000011
311211022111121102201212111
4103311201200201320003
5134313202440101042
62522115040440151
7200324615333065
oct23654140417003
94738447381774
101363140550147
11486117338042
121a0229019057
139b70b3a970c
1449d9518d735
15256d2231517
hex13d61821e03

1363140550147 has 2 divisors, whose sum is σ = 1363140550148. Its totient is φ = 1363140550146.

The previous prime is 1363140550111. The next prime is 1363140550207. The reversal of 1363140550147 is 7410550413631.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1363140550147 is a prime.

It is not a weakly prime, because it can be changed into another prime (1363140556147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681570275073 + 681570275074.

It is an arithmetic number, because the mean of its divisors is an integer number (681570275074).

Almost surely, 21363140550147 is an apocalyptic number.

1363140550147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1363140550147 is an equidigital number, since it uses as much as digits as its factorization.

1363140550147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

Adding to 1363140550147 its reverse (7410550413631), we get a palindrome (8773690963778).

The spelling of 1363140550147 in words is "one trillion, three hundred sixty-three billion, one hundred forty million, five hundred fifty thousand, one hundred forty-seven".