Base | Representation |
---|---|
bin | 1100011001101000101101… |
… | …1100010100011001110100 |
3 | 1210021110012022201202012000 |
4 | 3012122023130110121310 |
5 | 3241342042301413012 |
6 | 44555344420455300 |
7 | 2605031150562303 |
oct | 306321334243164 |
9 | 53243168652160 |
10 | 13634565654132 |
11 | 438742894a8a5 |
12 | 164257854a530 |
13 | 77b970860bb7 |
14 | 351cb8c3043a |
15 | 1899edd89ddc |
hex | c668b714674 |
13634565654132 has 48 divisors (see below), whose sum is σ = 36304248899520. Its totient is φ = 4422021291936.
The previous prime is 13634565654023. The next prime is 13634565654187. The reversal of 13634565654132 is 23145656543631.
13634565654132 is a `hidden beast` number, since 1 + 3 + 6 + 3 + 4 + 5 + 6 + 565 + 41 + 32 = 666.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1706022738 + ... + 1706030729.
It is an arithmetic number, because the mean of its divisors is an integer number (756338518740).
Almost surely, 213634565654132 is an apocalyptic number.
13634565654132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13634565654132 is an abundant number, since it is smaller than the sum of its proper divisors (22669683245388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13634565654132 is a wasteful number, since it uses less digits than its factorization.
13634565654132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3412053517 (or 3412053509 counting only the distinct ones).
The product of its digits is 23328000, while the sum is 54.
The spelling of 13634565654132 in words is "thirteen trillion, six hundred thirty-four billion, five hundred sixty-five million, six hundred fifty-four thousand, one hundred thirty-two".
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