Base | Representation |
---|---|
bin | 111111100000100010… |
… | …0100010000110110100 |
3 | 111001000210000020111222 |
4 | 1333001010202012310 |
5 | 4213303043132030 |
6 | 142353100445512 |
7 | 12565462610150 |
oct | 1770104420664 |
9 | 431023006458 |
10 | 136383177140 |
11 | 52926825641 |
12 | 22522549898 |
13 | cb26471922 |
14 | 685b140060 |
15 | 383343a3e5 |
hex | 1fc11221b4 |
136383177140 has 48 divisors (see below), whose sum is σ = 327342489600. Its totient is φ = 46756680192.
The previous prime is 136383177131. The next prime is 136383177157. The reversal of 136383177140 is 41771383631.
It is a super-3 number, since 3×1363831771403 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136383177091 and 136383177100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2843276 + ... + 2890844.
It is an arithmetic number, because the mean of its divisors is an integer number (6819635200).
Almost surely, 2136383177140 is an apocalyptic number.
136383177140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
136383177140 is an abundant number, since it is smaller than the sum of its proper divisors (190959312460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136383177140 is a wasteful number, since it uses less digits than its factorization.
136383177140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68064 (or 68062 counting only the distinct ones).
The product of its (nonzero) digits is 254016, while the sum is 44.
The spelling of 136383177140 in words is "one hundred thirty-six billion, three hundred eighty-three million, one hundred seventy-seven thousand, one hundred forty".
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