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136412163047 is a prime number
BaseRepresentation
bin111111100001011001…
…1000110101111100111
3111001002210112212201002
41333002303012233213
54213333003204142
6142400014023515
712566264153156
oct1770263065747
9431083485632
10136412163047
1152941123136
12225301a7b9b
13cb2c480154
146860d2759d
153835c63a32
hex1fc2cc6be7

136412163047 has 2 divisors, whose sum is σ = 136412163048. Its totient is φ = 136412163046.

The previous prime is 136412163031. The next prime is 136412163059. The reversal of 136412163047 is 740361214631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136412163047 - 24 = 136412163031 is a prime.

It is a super-2 number, since 2×1364121630472 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 136412163047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136412163247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68206081523 + 68206081524.

It is an arithmetic number, because the mean of its divisors is an integer number (68206081524).

Almost surely, 2136412163047 is an apocalyptic number.

136412163047 is a deficient number, since it is larger than the sum of its proper divisors (1).

136412163047 is an equidigital number, since it uses as much as digits as its factorization.

136412163047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 38.

Adding to 136412163047 its reverse (740361214631), we get a palindrome (876773377678).

The spelling of 136412163047 in words is "one hundred thirty-six billion, four hundred twelve million, one hundred sixty-three thousand, forty-seven".