13642001 has 2 divisors, whose sum is σ = 13642002. Its totient is φ = 13642000.

The previous prime is 13641989. The next prime is 13642003. The reversal of 13642001 is 10024631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11723776 + 1918225 = 3424^2 + 1385^2 .

It is a cyclic number.

It is not a de Polignac number, because 13642001 - 2¹⁴ = 13625617 is a prime.

It is a super-2 number, since 2×13642001² = 372208382568002, which contains 22 as substring.

Together with 13642003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13642003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821000 + 6821001.

It is an arithmetic number, because the mean of its divisors is an integer number (6821001).

Almost surely, 2^13642001 is an apocalyptic number.

It is an amenable number.

13642001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13642001 is an equidigital number, since it uses as much as digits as its factorization.

13642001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 13642001 is about 3693.5079531524. The cubic root of 13642001 is about 238.9421088406.

Adding to 13642001 its reverse (10024631), we get a palindrome (23666632).

The spelling of 13642001 in words is "thirteen million, six hundred forty-two thousand, one".