13643054404013 has 2 divisors, whose sum is σ = 13643054404014. Its totient is φ = 13643054404012.

The previous prime is 13643054403971. The next prime is 13643054404037. The reversal of 13643054404013 is 31040445034631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9560383608169 + 4082670795844 = 3091987^2 + 2020562^2 .

It is an emirp because it is prime and its reverse (31040445034631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13643054404013 - 2²⁴ = 13643037626797 is a prime.

It is a super-2 number, since 2×13643054404013² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13643054404073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821527202006 + 6821527202007.

It is an arithmetic number, because the mean of its divisors is an integer number (6821527202007).

Almost surely, 2^{13643054404013} is an apocalyptic number.

It is an amenable number.

13643054404013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13643054404013 is an equidigital number, since it uses as much as digits as its factorization.

13643054404013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 13643054404013 its reverse (31040445034631), we get a palindrome (44683499438644).

The spelling of 13643054404013 in words is "thirteen trillion, six hundred forty-three billion, fifty-four million, four hundred four thousand, thirteen".