13643054404037 has 2 divisors, whose sum is σ = 13643054404038. Its totient is φ = 13643054404036.

The previous prime is 13643054404013. The next prime is 13643054404073. The reversal of 13643054404037 is 73040445034631.

Together with next prime (13643054404073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13409431048321 + 233623355716 = 3661889^2 + 483346^2 .

It is a cyclic number.

It is not a de Polignac number, because 13643054404037 - 2²⁰ = 13643053355461 is a prime.

It is a super-2 number, since 2×13643054404037² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13643054404937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821527202018 + 6821527202019.

It is an arithmetic number, because the mean of its divisors is an integer number (6821527202019).

Almost surely, 2^{13643054404037} is an apocalyptic number.

It is an amenable number.

13643054404037 is a deficient number, since it is larger than the sum of its proper divisors (1).

13643054404037 is an equidigital number, since it uses as much as digits as its factorization.

13643054404037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 44.

Adding to 13643054404037 its reverse (73040445034631), we get a palindrome (86683499438668).

The spelling of 13643054404037 in words is "thirteen trillion, six hundred forty-three billion, fifty-four million, four hundred four thousand, thirty-seven".