Base | Representation |
---|---|
bin | 1100011010001000100000… |
… | …1100001100111110010101 |
3 | 1210022021020011112212220212 |
4 | 3012202020030030332111 |
5 | 3242012032331013331 |
6 | 45003315403335205 |
7 | 2605452522235004 |
oct | 306421014147625 |
9 | 53267204485825 |
10 | 13643101032341 |
11 | 4390008948880 |
12 | 164415ab21505 |
13 | 77c700c95051 |
14 | 35248865cc3b |
15 | 189d4d38ad2b |
hex | c688830cf95 |
13643101032341 has 32 divisors (see below), whose sum is σ = 15058871118720. Its totient is φ = 12257062048000.
The previous prime is 13643101032313. The next prime is 13643101032359. The reversal of 13643101032341 is 14323010134631.
It is not a de Polignac number, because 13643101032341 - 210 = 13643101031317 is a prime.
It is a super-2 number, since 2×136431010323412 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13643101032298 and 13643101032307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13643101032941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1445698475 + ... + 1445707911.
It is an arithmetic number, because the mean of its divisors is an integer number (470589722460).
Almost surely, 213643101032341 is an apocalyptic number.
13643101032341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13643101032341 is a deficient number, since it is larger than the sum of its proper divisors (1415770086379).
13643101032341 is a wasteful number, since it uses less digits than its factorization.
13643101032341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11845.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 13643101032341 its reverse (14323010134631), we get a palindrome (27966111166972).
The spelling of 13643101032341 in words is "thirteen trillion, six hundred forty-three billion, one hundred one million, thirty-two thousand, three hundred forty-one".
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