1364400031 has 4 divisors (see below), whose sum is σ = 1364925600. Its totient is φ = 1363874464.

The previous prime is 1364400029. The next prime is 1364400067. The reversal of 1364400031 is 1300044631.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1300044631 = 2593 ⋅501367.

It is a cyclic number.

It is not a de Polignac number, because 1364400031 - 2¹ = 1364400029 is a prime.

It is a super-2 number, since 2×1364400031² = 3723174889185601922, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1364399975 and 1364400011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1364400001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258871 + ... + 264088.

It is an arithmetic number, because the mean of its divisors is an integer number (341231400).

Almost surely, 2^1364400031 is an apocalyptic number.

1364400031 is a deficient number, since it is larger than the sum of its proper divisors (525569).

1364400031 is an equidigital number, since it uses as much as digits as its factorization.

1364400031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 525568.

The product of its (nonzero) digits is 864, while the sum is 22.

The square root of 1364400031 is about 36937.7859515158. The cubic root of 1364400031 is about 1109.1252017731.

Adding to 1364400031 its reverse (1300044631), we get a palindrome (2664444662).

The spelling of 1364400031 in words is "one billion, three hundred sixty-four million, four hundred thousand, thirty-one".