Base | Representation |
---|---|
bin | 10011110110101100100… |
… | …101010110101110101011 |
3 | 11211102202101111211020111 |
4 | 103312230211112232223 |
5 | 134323242411401121 |
6 | 2522444033235151 |
7 | 200401051356556 |
oct | 23665445265653 |
9 | 4742671454214 |
10 | 1364400106411 |
11 | 486703321331 |
12 | 1a051aa02ab7 |
13 | 9b87c323b94 |
14 | 4a07458369d |
15 | 25757ad32e1 |
hex | 13dac956bab |
1364400106411 has 4 divisors (see below), whose sum is σ = 1423721850192. Its totient is φ = 1305078362632.
The previous prime is 1364400106409. The next prime is 1364400106451. The reversal of 1364400106411 is 1146010044631.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1364400106411 - 21 = 1364400106409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1364400106451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29660871856 + ... + 29660871901.
It is an arithmetic number, because the mean of its divisors is an integer number (355930462548).
Almost surely, 21364400106411 is an apocalyptic number.
1364400106411 is a deficient number, since it is larger than the sum of its proper divisors (59321743781).
1364400106411 is an equidigital number, since it uses as much as digits as its factorization.
1364400106411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59321743780.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 1364400106411 in words is "one trillion, three hundred sixty-four billion, four hundred million, one hundred six thousand, four hundred eleven".
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