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13644557473 is a prime number
BaseRepresentation
bin11001011010100011…
…10110110010100001
31022012220122100002111
430231101312302201
5210421001314343
610133534115321
7662060552641
oct145521666241
938186570074
1013644557473
115871aa6a88
12278964bb41
131395a9b661
149361d0521
1554cd21c9d
hex32d476ca1

13644557473 has 2 divisors, whose sum is σ = 13644557474. Its totient is φ = 13644557472.

The previous prime is 13644557471. The next prime is 13644557519. The reversal of 13644557473 is 37475544631.

13644557473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10361611264 + 3282946209 = 101792^2 + 57297^2 .

It is a cyclic number.

It is not a de Polignac number, because 13644557473 - 21 = 13644557471 is a prime.

Together with 13644557471, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13644557471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822278736 + 6822278737.

It is an arithmetic number, because the mean of its divisors is an integer number (6822278737).

Almost surely, 213644557473 is an apocalyptic number.

It is an amenable number.

13644557473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13644557473 is an equidigital number, since it uses as much as digits as its factorization.

13644557473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4233600, while the sum is 49.

The spelling of 13644557473 in words is "thirteen billion, six hundred forty-four million, five hundred fifty-seven thousand, four hundred seventy-three".