Base | Representation |
---|---|
bin | 11001011011001111… |
… | …11011011001111101 |
3 | 1022020022112022002121 |
4 | 30231213323121331 |
5 | 210423441443144 |
6 | 10134302122541 |
7 | 662161001653 |
oct | 145547733175 |
9 | 38208468077 |
10 | 13650343549 |
11 | 5875299167 |
12 | 278b580451 |
13 | 139704617b |
14 | 936c98dd3 |
15 | 54d5b6384 |
hex | 32d9fb67d |
13650343549 has 2 divisors, whose sum is σ = 13650343550. Its totient is φ = 13650343548.
The previous prime is 13650343493. The next prime is 13650343573. The reversal of 13650343549 is 94534305631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11429106649 + 2221236900 = 106907^2 + 47130^2 .
It is a cyclic number.
It is not a de Polignac number, because 13650343549 - 29 = 13650343037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13650343349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6825171774 + 6825171775.
It is an arithmetic number, because the mean of its divisors is an integer number (6825171775).
Almost surely, 213650343549 is an apocalyptic number.
It is an amenable number.
13650343549 is a deficient number, since it is larger than the sum of its proper divisors (1).
13650343549 is an equidigital number, since it uses as much as digits as its factorization.
13650343549 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 43.
The spelling of 13650343549 in words is "thirteen billion, six hundred fifty million, three hundred forty-three thousand, five hundred forty-nine".
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