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136510053 = 345503351
BaseRepresentation
bin10000010001011…
…11101001100101
3100111212102120220
420020233221211
5234421310203
621313514553
73245213331
oct1010575145
9314772526
10136510053
1170069029
1239872a59
13223879a4
14141b67c1
15beb7653
hex822fa65

136510053 has 4 divisors (see below), whose sum is σ = 182013408. Its totient is φ = 91006700.

The previous prime is 136510001. The next prime is 136510061. The reversal of 136510053 is 350015631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 136510053 - 28 = 136509797 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136510063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22751673 + ... + 22751678.

It is an arithmetic number, because the mean of its divisors is an integer number (45503352).

Almost surely, 2136510053 is an apocalyptic number.

It is an amenable number.

136510053 is a deficient number, since it is larger than the sum of its proper divisors (45503355).

136510053 is an equidigital number, since it uses as much as digits as its factorization.

136510053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45503354.

The product of its (nonzero) digits is 1350, while the sum is 24.

The square root of 136510053 is about 11683.7516663099. The cubic root of 136510053 is about 514.8984033101.

Adding to 136510053 its reverse (350015631), we get a palindrome (486525684).

The spelling of 136510053 in words is "one hundred thirty-six million, five hundred ten thousand, fifty-three".

Divisors: 1 3 45503351 136510053