Base | Representation |
---|---|
bin | 11001011011011000… |
… | …01010000001101101 |
3 | 1022020101121121121211 |
4 | 30231230022001231 |
5 | 210424232431023 |
6 | 10134341554421 |
7 | 662203266433 |
oct | 145554120155 |
9 | 38211547554 |
10 | 13651452013 |
11 | 5875985a51 |
12 | 278ba15a11 |
13 | 1397343874 |
14 | 9370a6d53 |
15 | 54d734a0d |
hex | 32db0a06d |
13651452013 has 8 divisors (see below), whose sum is σ = 14490895032. Its totient is φ = 12816055296.
The previous prime is 13651451999. The next prime is 13651452019. The reversal of 13651452013 is 31025415631.
It can be written as a sum of positive squares in 4 ways, for example, as 7555434084 + 6096017929 = 86922^2 + 78077^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13651452013 - 29 = 13651451501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13651452019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1004620 + ... + 1018117.
It is an arithmetic number, because the mean of its divisors is an integer number (1811361879).
Almost surely, 213651452013 is an apocalyptic number.
It is an amenable number.
13651452013 is a deficient number, since it is larger than the sum of its proper divisors (839443019).
13651452013 is a wasteful number, since it uses less digits than its factorization.
13651452013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2023151.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 13651452013 its reverse (31025415631), we get a palindrome (44676867644).
The spelling of 13651452013 in words is "thirteen billion, six hundred fifty-one million, four hundred fifty-two thousand, thirteen".
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