13656220064653 has 2 divisors, whose sum is σ = 13656220064654. Its totient is φ = 13656220064652.

The previous prime is 13656220064609. The next prime is 13656220064657. The reversal of 13656220064653 is 35646002265631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13272629358244 + 383590706409 = 3643162^2 + 619347^2 .

It is a cyclic number.

It is not a de Polignac number, because 13656220064653 - 2⁹ = 13656220064141 is a prime.

It is a super-3 number, since 3×13656220064653³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13656220064597 and 13656220064606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13656220064657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6828110032326 + 6828110032327.

It is an arithmetic number, because the mean of its divisors is an integer number (6828110032327).

Almost surely, 2^{13656220064653} is an apocalyptic number.

It is an amenable number.

13656220064653 is a deficient number, since it is larger than the sum of its proper divisors (1).

13656220064653 is an equidigital number, since it uses as much as digits as its factorization.

13656220064653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4665600, while the sum is 49.

The spelling of 13656220064653 in words is "thirteen trillion, six hundred fifty-six billion, two hundred twenty million, sixty-four thousand, six hundred fifty-three".