Base | Representation |
---|---|
bin | 11111000011110110001100… |
… | …001010000111100000010111 |
3 | 122220200012020202000110101001 |
4 | 133003312030022013200113 |
5 | 120401104023243433303 |
6 | 1202310525121044131 |
7 | 40526204112166414 |
oct | 3703661412074027 |
9 | 586605222013331 |
10 | 136603786311703 |
11 | 3a5873821351a7 |
12 | 133a288b786647 |
13 | 5b2b8b2b262b9 |
14 | 25a393103d10b |
15 | 10bd5a09b431d |
hex | 7c3d8c287817 |
136603786311703 has 2 divisors, whose sum is σ = 136603786311704. Its totient is φ = 136603786311702.
The previous prime is 136603786311689. The next prime is 136603786311737. The reversal of 136603786311703 is 307113687306631.
It is a weak prime.
It is an emirp because it is prime and its reverse (307113687306631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136603786311703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136603786311743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68301893155851 + 68301893155852.
It is an arithmetic number, because the mean of its divisors is an integer number (68301893155852).
Almost surely, 2136603786311703 is an apocalyptic number.
136603786311703 is a deficient number, since it is larger than the sum of its proper divisors (1).
136603786311703 is an equidigital number, since it uses as much as digits as its factorization.
136603786311703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6858432, while the sum is 55.
The spelling of 136603786311703 in words is "one hundred thirty-six trillion, six hundred three billion, seven hundred eighty-six million, three hundred eleven thousand, seven hundred three".
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