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136642117 is a prime number
BaseRepresentation
bin10000010010011…
…11111001000101
3100112010010202011
420021033321011
5234440021432
621320414221
73246303343
oct1011177105
9315103664
10136642117
1170149277
1239917371
1322402b31
141420c993
15bee1847
hex824fe45

136642117 has 2 divisors, whose sum is σ = 136642118. Its totient is φ = 136642116.

The previous prime is 136642087. The next prime is 136642133. The reversal of 136642117 is 711246631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126202756 + 10439361 = 11234^2 + 3231^2 .

It is an emirp because it is prime and its reverse (711246631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136642117 - 215 = 136609349 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136642157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68321058 + 68321059.

It is an arithmetic number, because the mean of its divisors is an integer number (68321059).

Almost surely, 2136642117 is an apocalyptic number.

It is an amenable number.

136642117 is a deficient number, since it is larger than the sum of its proper divisors (1).

136642117 is an equidigital number, since it uses as much as digits as its factorization.

136642117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048, while the sum is 31.

The square root of 136642117 is about 11689.4019094221. The cubic root of 136642117 is about 515.0643926145.

Adding to 136642117 its reverse (711246631), we get a palindrome (847888748).

The spelling of 136642117 in words is "one hundred thirty-six million, six hundred forty-two thousand, one hundred seventeen".