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136651440452519 is a prime number
BaseRepresentation
bin11111000100100010100100…
…100100001111001110100111
3122220211202020211200122011102
4133010202210210033032213
5120402344122223440034
61202344445522430315
740532512040540516
oct3704424444171647
9586752224618142
10136651440452519
113a5a5606704553
12133abb6ab0239b
135b33238885465
1425a5d71da467d
1510be93e42997e
hex7c48a490f3a7

136651440452519 has 2 divisors, whose sum is σ = 136651440452520. Its totient is φ = 136651440452518.

The previous prime is 136651440452491. The next prime is 136651440452561. The reversal of 136651440452519 is 915254044156631.

It is a weak prime.

It is an emirp because it is prime and its reverse (915254044156631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136651440452519 - 212 = 136651440448423 is a prime.

It is a super-2 number, since 2×1366514404525192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136651440452119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68325720226259 + 68325720226260.

It is an arithmetic number, because the mean of its divisors is an integer number (68325720226260).

Almost surely, 2136651440452519 is an apocalyptic number.

136651440452519 is a deficient number, since it is larger than the sum of its proper divisors (1).

136651440452519 is an equidigital number, since it uses as much as digits as its factorization.

136651440452519 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552000, while the sum is 56.

The spelling of 136651440452519 in words is "one hundred thirty-six trillion, six hundred fifty-one billion, four hundred forty million, four hundred fifty-two thousand, five hundred nineteen".