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136734734103743 is a prime number
BaseRepresentation
bin11111000101110000001001…
…010000010011010010111111
3122221010201020201101112020202
4133011300021100103102333
5120410230213412304433
61202451023014434115
740541521115103026
oct3705601120232277
9587121221345222
10136734734103743
113a627969809536
121340413596293b
135b3b051188909
1425a9dd43458bd
1510c1bb6b44ee8
hex7c5c094134bf

136734734103743 has 2 divisors, whose sum is σ = 136734734103744. Its totient is φ = 136734734103742.

The previous prime is 136734734103701. The next prime is 136734734103749. The reversal of 136734734103743 is 347301437437631.

It is a strong prime.

It is an emirp because it is prime and its reverse (347301437437631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136734734103743 - 218 = 136734733841599 is a prime.

It is a super-2 number, since 2×1367347341037432 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136734734103749) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68367367051871 + 68367367051872.

It is an arithmetic number, because the mean of its divisors is an integer number (68367367051872).

Almost surely, 2136734734103743 is an apocalyptic number.

136734734103743 is a deficient number, since it is larger than the sum of its proper divisors (1).

136734734103743 is an equidigital number, since it uses as much as digits as its factorization.

136734734103743 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32006016, while the sum is 56.

The spelling of 136734734103743 in words is "one hundred thirty-six trillion, seven hundred thirty-four billion, seven hundred thirty-four million, one hundred three thousand, seven hundred forty-three".