Base | Representation |
---|---|
bin | 11111000110010010011101… |
… | …111011001101111101110111 |
3 | 122221021020101010201112222002 |
4 | 133012102131323031331313 |
5 | 120411331203024323224 |
6 | 1202520000012125515 |
7 | 40544264312060606 |
oct | 3706223573157567 |
9 | 587236333645862 |
10 | 136771588120439 |
11 | 3a641560958778 |
12 | 1340b30016689b |
13 | 5b4167553309c |
14 | 25abaccb89a3d |
15 | 10c2b2234d9ae |
hex | 7c649decdf77 |
136771588120439 has 2 divisors, whose sum is σ = 136771588120440. Its totient is φ = 136771588120438.
The previous prime is 136771588120403. The next prime is 136771588120463. The reversal of 136771588120439 is 934021885177631.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136771588120439 - 28 = 136771588120183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136771588122439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68385794060219 + 68385794060220.
It is an arithmetic number, because the mean of its divisors is an integer number (68385794060220).
It is a 1-persistent number, because it is pandigital, but 2⋅136771588120439 = 273543176240878 is not.
Almost surely, 2136771588120439 is an apocalyptic number.
136771588120439 is a deficient number, since it is larger than the sum of its proper divisors (1).
136771588120439 is an equidigital number, since it uses as much as digits as its factorization.
136771588120439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60963840, while the sum is 65.
The spelling of 136771588120439 in words is "one hundred thirty-six trillion, seven hundred seventy-one billion, five hundred eighty-eight million, one hundred twenty thousand, four hundred thirty-nine".
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