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136801069655893 is a prime number
BaseRepresentation
bin11111000110101101111011…
…001010010110011101010101
3122221101001110202102201200121
4133012231323022112131111
5120412322042312442033
61202541313243511541
740546360015020166
oct3706557312263525
9587331422381617
10136801069655893
113a65300a473705
1213414b695285b1
135b44393379816
1425ad2c83d376d
1510c379a6b362d
hex7c6b7b296755

136801069655893 has 2 divisors, whose sum is σ = 136801069655894. Its totient is φ = 136801069655892.

The previous prime is 136801069655891. The next prime is 136801069655983. The reversal of 136801069655893 is 398556960108631.

Together with next prime (136801069655983) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131667868014244 + 5133201641649 = 11474662^2 + 2265657^2 .

It is a cyclic number.

It is not a de Polignac number, because 136801069655893 - 21 = 136801069655891 is a prime.

Together with 136801069655891, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136801069655891) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68400534827946 + 68400534827947.

It is an arithmetic number, because the mean of its divisors is an integer number (68400534827947).

Almost surely, 2136801069655893 is an apocalyptic number.

It is an amenable number.

136801069655893 is a deficient number, since it is larger than the sum of its proper divisors (1).

136801069655893 is an equidigital number, since it uses as much as digits as its factorization.

136801069655893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 251942400, while the sum is 70.

The spelling of 136801069655893 in words is "one hundred thirty-six trillion, eight hundred one billion, sixty-nine million, six hundred fifty-five thousand, eight hundred ninety-three".