Base | Representation |
---|---|
bin | 11001011110111111… |
… | …01110001111010011 |
3 | 1022022111121202101122 |
4 | 30233133232033103 |
5 | 211010011400044 |
6 | 10141343152455 |
7 | 663021633632 |
oct | 145737561723 |
9 | 38274552348 |
10 | 13681746899 |
11 | 5890a97a47 |
12 | 2799ba572b |
13 | 13a06bcb32 |
14 | 93b111519 |
15 | 55121adee |
hex | 32f7ee3d3 |
13681746899 has 2 divisors, whose sum is σ = 13681746900. Its totient is φ = 13681746898.
The previous prime is 13681746887. The next prime is 13681746901. The reversal of 13681746899 is 99864718631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13681746899 - 212 = 13681742803 is a prime.
It is a super-2 number, since 2×136817468992 (a number of 21 digits) contains 22 as substring.
Together with 13681746901, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13681746839) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840873449 + 6840873450.
It is an arithmetic number, because the mean of its divisors is an integer number (6840873450).
Almost surely, 213681746899 is an apocalyptic number.
13681746899 is a deficient number, since it is larger than the sum of its proper divisors (1).
13681746899 is an equidigital number, since it uses as much as digits as its factorization.
13681746899 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15676416, while the sum is 62.
Adding to 13681746899 its sum of digits (62), we get a square (13681746961 = 1169692).
The spelling of 13681746899 in words is "thirteen billion, six hundred eighty-one million, seven hundred forty-six thousand, eight hundred ninety-nine".
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