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1368321433 is a prime number
BaseRepresentation
bin101000110001110…
…1110110110011001
310112100201221010121
41101203232312121
510300242241213
6343435513241
745623353213
oct12143566631
93470657117
101368321433
11642422166
123222b8821
1318a63976b
14cda275b3
15801d888d
hex518eed99

1368321433 has 2 divisors, whose sum is σ = 1368321434. Its totient is φ = 1368321432.

The previous prime is 1368321419. The next prime is 1368321467. The reversal of 1368321433 is 3341238631.

It is an a-pointer prime, because the next prime (1368321467) can be obtained adding 1368321433 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1095146649 + 273174784 = 33093^2 + 16528^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1368321433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1368321133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684160716 + 684160717.

It is an arithmetic number, because the mean of its divisors is an integer number (684160717).

Almost surely, 21368321433 is an apocalyptic number.

It is an amenable number.

1368321433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1368321433 is an equidigital number, since it uses as much as digits as its factorization.

1368321433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 34.

The square root of 1368321433 is about 36990.8290391010. The cubic root of 1368321433 is about 1110.1867588796.

The spelling of 1368321433 in words is "one billion, three hundred sixty-eight million, three hundred twenty-one thousand, four hundred thirty-three".