Base | Representation |
---|---|
bin | 101000110001110… |
… | …1110110110011001 |
3 | 10112100201221010121 |
4 | 1101203232312121 |
5 | 10300242241213 |
6 | 343435513241 |
7 | 45623353213 |
oct | 12143566631 |
9 | 3470657117 |
10 | 1368321433 |
11 | 642422166 |
12 | 3222b8821 |
13 | 18a63976b |
14 | cda275b3 |
15 | 801d888d |
hex | 518eed99 |
1368321433 has 2 divisors, whose sum is σ = 1368321434. Its totient is φ = 1368321432.
The previous prime is 1368321419. The next prime is 1368321467. The reversal of 1368321433 is 3341238631.
It is an a-pointer prime, because the next prime (1368321467) can be obtained adding 1368321433 to its sum of digits (34).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1095146649 + 273174784 = 33093^2 + 16528^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1368321433 is a prime.
It is not a weakly prime, because it can be changed into another prime (1368321133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684160716 + 684160717.
It is an arithmetic number, because the mean of its divisors is an integer number (684160717).
Almost surely, 21368321433 is an apocalyptic number.
It is an amenable number.
1368321433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1368321433 is an equidigital number, since it uses as much as digits as its factorization.
1368321433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 34.
The square root of 1368321433 is about 36990.8290391010. The cubic root of 1368321433 is about 1110.1867588796.
The spelling of 1368321433 in words is "one billion, three hundred sixty-eight million, three hundred twenty-one thousand, four hundred thirty-three".
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