Base | Representation |
---|---|
bin | 11001100000000110… |
… | …01011000110001110 |
3 | 1022100011002220022211 |
4 | 30300003023012032 |
5 | 211014401241032 |
6 | 10142314301034 |
7 | 663163630633 |
oct | 146003130616 |
9 | 38304086284 |
10 | 13691040142 |
11 | 589626510a |
12 | 27a112777a |
13 | 13a25c4ab0 |
14 | 93c45018a |
15 | 551e54747 |
hex | 3300cb18e |
13691040142 has 8 divisors (see below), whose sum is σ = 22116295656. Its totient is φ = 6318941592.
The previous prime is 13691040137. The next prime is 13691040149. The reversal of 13691040142 is 24104019631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13691040149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263289208 + ... + 263289259.
It is an arithmetic number, because the mean of its divisors is an integer number (2764536957).
Almost surely, 213691040142 is an apocalyptic number.
13691040142 is a deficient number, since it is larger than the sum of its proper divisors (8425255514).
13691040142 is a wasteful number, since it uses less digits than its factorization.
13691040142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 526578482.
The product of its (nonzero) digits is 5184, while the sum is 31.
Adding to 13691040142 its reverse (24104019631), we get a palindrome (37795059773).
The spelling of 13691040142 in words is "thirteen billion, six hundred ninety-one million, forty thousand, one hundred forty-two".
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