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13693408153 is a prime number
BaseRepresentation
bin11001100000011000…
…01101001110011001
31022100022120012121221
430300030031032121
5211021003030103
610142441132041
7663223022515
oct146014151631
938308505557
1013693408153
115897632247
1227a1a8a021
1313a2c43899
1493c8a9145
155522711bd
hex33030d399

13693408153 has 2 divisors, whose sum is σ = 13693408154. Its totient is φ = 13693408152.

The previous prime is 13693408151. The next prime is 13693408187. The reversal of 13693408153 is 35180439631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13499418969 + 193989184 = 116187^2 + 13928^2 .

It is an emirp because it is prime and its reverse (35180439631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13693408153 - 21 = 13693408151 is a prime.

Together with 13693408151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13693408151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6846704076 + 6846704077.

It is an arithmetic number, because the mean of its divisors is an integer number (6846704077).

Almost surely, 213693408153 is an apocalyptic number.

It is an amenable number.

13693408153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13693408153 is an equidigital number, since it uses as much as digits as its factorization.

13693408153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 13693408153 in words is "thirteen billion, six hundred ninety-three million, four hundred eight thousand, one hundred fifty-three".