Base | Representation |
---|---|
bin | 11001100000011000… |
… | …01101001110010111 |
3 | 1022100022120012121212 |
4 | 30300030031032113 |
5 | 211021003030101 |
6 | 10142441132035 |
7 | 663223022513 |
oct | 146014151627 |
9 | 38308505555 |
10 | 13693408151 |
11 | 5897632245 |
12 | 27a1a8a01b |
13 | 13a2c43897 |
14 | 93c8a9143 |
15 | 5522711bb |
hex | 33030d397 |
13693408151 has 2 divisors, whose sum is σ = 13693408152. Its totient is φ = 13693408150.
The previous prime is 13693408121. The next prime is 13693408153. The reversal of 13693408151 is 15180439631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13693408151 - 210 = 13693407127 is a prime.
Together with 13693408153, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13693408099 and 13693408108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13693408153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6846704075 + 6846704076.
It is an arithmetic number, because the mean of its divisors is an integer number (6846704076).
Almost surely, 213693408151 is an apocalyptic number.
13693408151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13693408151 is an equidigital number, since it uses as much as digits as its factorization.
13693408151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 41.
The spelling of 13693408151 in words is "thirteen billion, six hundred ninety-three million, four hundred eight thousand, one hundred fifty-one".
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