1369714380131 has 2 divisors, whose sum is σ = 1369714380132. Its totient is φ = 1369714380130.

The previous prime is 1369714380113. The next prime is 1369714380149. The reversal of 1369714380131 is 1310834179631.

Together with previous prime (1369714380113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1369714380113) and next prime (1369714380149).

It is an emirp because it is prime and its reverse (1310834179631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1369714380131 - 2¹⁴ = 1369714363747 is a prime.

It is a super-2 number, since 2×1369714380131² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1369714383131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684857190065 + 684857190066.

It is an arithmetic number, because the mean of its divisors is an integer number (684857190066).

Almost surely, 2^{1369714380131} is an apocalyptic number.

1369714380131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1369714380131 is an equidigital number, since it uses as much as digits as its factorization.

1369714380131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 47.

The spelling of 1369714380131 in words is "one trillion, three hundred sixty-nine billion, seven hundred fourteen million, three hundred eighty thousand, one hundred thirty-one".