Search a number
-
+
1369714380149 is a prime number
BaseRepresentation
bin10011111011101001010…
…101101100110101110101
311211221110202020220022202
4103323221111230311311
5134420133340131044
62525123232434245
7200646541063163
oct23735125546565
94757422226282
101369714380149
114889900718a5
121a15626a8985
139c21830a45b
144a41a292233
1525969417c4e
hex13ee956cd75

1369714380149 has 2 divisors, whose sum is σ = 1369714380150. Its totient is φ = 1369714380148.

The previous prime is 1369714380131. The next prime is 1369714380211. The reversal of 1369714380149 is 9410834179631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1243871784100 + 125842596049 = 1115290^2 + 354743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1369714380149 - 216 = 1369714314613 is a prime.

It is a super-2 number, since 2×13697143801492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1369714380094 and 1369714380103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1369714310149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684857190074 + 684857190075.

It is an arithmetic number, because the mean of its divisors is an integer number (684857190075).

Almost surely, 21369714380149 is an apocalyptic number.

It is an amenable number.

1369714380149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1369714380149 is an equidigital number, since it uses as much as digits as its factorization.

1369714380149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3919104, while the sum is 56.

The spelling of 1369714380149 in words is "one trillion, three hundred sixty-nine billion, seven hundred fourteen million, three hundred eighty thousand, one hundred forty-nine".