Base | Representation |
---|---|
bin | 10011111011111100001… |
… | …111100101111011000111 |
3 | 11211222021212001121011011 |
4 | 103323330033211323013 |
5 | 134421311033433210 |
6 | 2525214522423051 |
7 | 200660441666134 |
oct | 23737417457307 |
9 | 4758255047134 |
10 | 1370031546055 |
11 | 489033100287 |
12 | 1a1630961a87 |
13 | 9c268c386a3 |
14 | 4a44a45358b |
15 | 259871b7d8a |
hex | 13efc3e5ec7 |
1370031546055 has 16 divisors (see below), whose sum is σ = 1648467606240. Its totient is φ = 1093072768128.
The previous prime is 1370031546049. The next prime is 1370031546067. The reversal of 1370031546055 is 5506451300731.
It is a cyclic number.
It is not a de Polignac number, because 1370031546055 - 23 = 1370031546047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1370031545999 and 1370031546017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17549689 + ... + 17627581.
It is an arithmetic number, because the mean of its divisors is an integer number (103029225390).
Almost surely, 21370031546055 is an apocalyptic number.
1370031546055 is a deficient number, since it is larger than the sum of its proper divisors (278436060185).
1370031546055 is an equidigital number, since it uses as much as digits as its factorization.
1370031546055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87330.
The product of its (nonzero) digits is 189000, while the sum is 40.
Adding to 1370031546055 its reverse (5506451300731), we get a palindrome (6876482846786).
The spelling of 1370031546055 in words is "one trillion, three hundred seventy billion, thirty-one million, five hundred forty-six thousand, fifty-five".
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