Base | Representation |
---|---|
bin | 10011111011111110111… |
… | …110100001000000001111 |
3 | 11211222102001100021110021 |
4 | 103323332332201000033 |
5 | 134421404303313403 |
6 | 2525223241323011 |
7 | 200661536521255 |
oct | 23737676410017 |
9 | 4758361307407 |
10 | 1370077401103 |
11 | 489056a7a914 |
12 | 1a1644196467 |
13 | 9c2755a2258 |
14 | 4a45258c5d5 |
15 | 2598b2248bd |
hex | 13efefa100f |
1370077401103 has 2 divisors, whose sum is σ = 1370077401104. Its totient is φ = 1370077401102.
The previous prime is 1370077401101. The next prime is 1370077401163. The reversal of 1370077401103 is 3011047700731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1370077401103 - 21 = 1370077401101 is a prime.
It is a super-2 number, since 2×13700774011032 (a number of 25 digits) contains 22 as substring.
Together with 1370077401101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1370077401101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685038700551 + 685038700552.
It is an arithmetic number, because the mean of its divisors is an integer number (685038700552).
Almost surely, 21370077401103 is an apocalyptic number.
1370077401103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370077401103 is an equidigital number, since it uses as much as digits as its factorization.
1370077401103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12348, while the sum is 34.
The spelling of 1370077401103 in words is "one trillion, three hundred seventy billion, seventy-seven million, four hundred one thousand, one hundred three".
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