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13713148303 is a prime number
BaseRepresentation
bin11001100010101111…
…00000100110001111
31022101200201010000121
430301113200212033
5211041031221203
610144424205411
7663552560131
oct146127404617
938350633017
1013713148303
1158a7795318
1227a8609867
1313a706594a
14941367051
15553d700bd
hex3315e098f

13713148303 has 2 divisors, whose sum is σ = 13713148304. Its totient is φ = 13713148302.

The previous prime is 13713148261. The next prime is 13713148321. The reversal of 13713148303 is 30384131731.

13713148303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13713148303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13713148363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6856574151 + 6856574152.

It is an arithmetic number, because the mean of its divisors is an integer number (6856574152).

Almost surely, 213713148303 is an apocalyptic number.

13713148303 is a deficient number, since it is larger than the sum of its proper divisors (1).

13713148303 is an equidigital number, since it uses as much as digits as its factorization.

13713148303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 34.

The spelling of 13713148303 in words is "thirteen billion, seven hundred thirteen million, one hundred forty-eight thousand, three hundred three".