Base | Representation |
---|---|
bin | 10011111101010010000… |
… | …110101001010010001111 |
3 | 11212010000020121022212121 |
4 | 103331102012221102033 |
5 | 134432233320303403 |
6 | 2530013501313411 |
7 | 201041233001143 |
oct | 23752206512217 |
9 | 4763006538777 |
10 | 1371472041103 |
11 | 48970223855a |
12 | 1a1973265867 |
13 | 9c4384c5118 |
14 | 4a5458a7223 |
15 | 25a1d8ab3bd |
hex | 13f521a948f |
1371472041103 has 2 divisors, whose sum is σ = 1371472041104. Its totient is φ = 1371472041102.
The previous prime is 1371472041083. The next prime is 1371472041143. The reversal of 1371472041103 is 3011402741731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1371472041103 - 213 = 1371472032911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1371472041143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685736020551 + 685736020552.
It is an arithmetic number, because the mean of its divisors is an integer number (685736020552).
Almost surely, 21371472041103 is an apocalyptic number.
1371472041103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371472041103 is an equidigital number, since it uses as much as digits as its factorization.
1371472041103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14112, while the sum is 34.
Adding to 1371472041103 its reverse (3011402741731), we get a palindrome (4382874782834).
The spelling of 1371472041103 in words is "one trillion, three hundred seventy-one billion, four hundred seventy-two million, forty-one thousand, one hundred three".
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