Base | Representation |
---|---|
bin | 1100011110011100010001… |
… | …1000011110001010011111 |
3 | 1210120100022001022121011011 |
4 | 3013213010120132022133 |
5 | 3244220133040403341 |
6 | 45101321013040051 |
7 | 2614013103320461 |
oct | 307470430361237 |
9 | 53510261277134 |
10 | 13717125325471 |
11 | 4409444706937 |
12 | 1656579626027 |
13 | 78669a088629 |
14 | 355cab910131 |
15 | 18bc31e1eb81 |
hex | c79c461e29f |
13717125325471 has 16 divisors (see below), whose sum is σ = 14083888435200. Its totient is φ = 13356029063520.
The previous prime is 13717125325441. The next prime is 13717125325487. The reversal of 13717125325471 is 17452352171731.
It is a cyclic number.
It is not a de Polignac number, because 13717125325471 - 25 = 13717125325439 is a prime.
It is a super-3 number, since 3×137171253254713 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13717125325441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1404571 + ... + 5422828.
It is an arithmetic number, because the mean of its divisors is an integer number (880243027200).
Almost surely, 213717125325471 is an apocalyptic number.
13717125325471 is a deficient number, since it is larger than the sum of its proper divisors (366763109729).
13717125325471 is a wasteful number, since it uses less digits than its factorization.
13717125325471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6827814.
The product of its digits is 1234800, while the sum is 49.
The spelling of 13717125325471 in words is "thirteen trillion, seven hundred seventeen billion, one hundred twenty-five million, three hundred twenty-five thousand, four hundred seventy-one".
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