Base | Representation |
---|---|
bin | 1100011110011100010001… |
… | …1000011110001010101111 |
3 | 1210120100022001022121011202 |
4 | 3013213010120132022233 |
5 | 3244220133040403422 |
6 | 45101321013040115 |
7 | 2614013103320513 |
oct | 307470430361257 |
9 | 53510261277152 |
10 | 13717125325487 |
11 | 4409444706951 |
12 | 165657962603b |
13 | 78669a08863c |
14 | 355cab910143 |
15 | 18bc31e1eb92 |
hex | c79c461e2af |
13717125325487 has 2 divisors, whose sum is σ = 13717125325488. Its totient is φ = 13717125325486.
The previous prime is 13717125325441. The next prime is 13717125325499. The reversal of 13717125325487 is 78452352171731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13717125325487 - 212 = 13717125321391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13717125625487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6858562662743 + 6858562662744.
It is an arithmetic number, because the mean of its divisors is an integer number (6858562662744).
Almost surely, 213717125325487 is an apocalyptic number.
13717125325487 is a deficient number, since it is larger than the sum of its proper divisors (1).
13717125325487 is an equidigital number, since it uses as much as digits as its factorization.
13717125325487 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9878400, while the sum is 56.
The spelling of 13717125325487 in words is "thirteen trillion, seven hundred seventeen billion, one hundred twenty-five million, three hundred twenty-five thousand, four hundred eighty-seven".
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