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13717423489493 is a prime number
BaseRepresentation
bin1100011110011101011000…
…1001111000000111010101
31210120101001211100220022002
43013213112021320013111
53244221240403130433
645101410343445045
72614023353552363
oct307472611700725
953511054326262
1013717423489493
114409587a46989
121656641456785
13786716a92849
14355cd9366633
1518bc4d1b99e8
hexc79d62781d5

13717423489493 has 2 divisors, whose sum is σ = 13717423489494. Its totient is φ = 13717423489492.

The previous prime is 13717423489487. The next prime is 13717423489589. The reversal of 13717423489493 is 39498432471731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8556198309604 + 5161225179889 = 2925098^2 + 2271833^2 .

It is a cyclic number.

It is not a de Polignac number, because 13717423489493 - 224 = 13717406712277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13717423489463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6858711744746 + 6858711744747.

It is an arithmetic number, because the mean of its divisors is an integer number (6858711744747).

Almost surely, 213717423489493 is an apocalyptic number.

It is an amenable number.

13717423489493 is a deficient number, since it is larger than the sum of its proper divisors (1).

13717423489493 is an equidigital number, since it uses as much as digits as its factorization.

13717423489493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 109734912, while the sum is 65.

The spelling of 13717423489493 in words is "thirteen trillion, seven hundred seventeen billion, four hundred twenty-three million, four hundred eighty-nine thousand, four hundred ninety-three".