Base | Representation |
---|---|
bin | 11111001111110010001000… |
… | …010011100010001000011011 |
3 | 200000120121112001110211222210 |
4 | 133033302020103202020123 |
5 | 121003023433432042411 |
6 | 1204135424122050203 |
7 | 40642363220126613 |
oct | 3717621023421033 |
9 | 600517461424883 |
10 | 137424060424731 |
11 | 3a873242521103 |
12 | 134b5853949963 |
13 | 5b8b0581b3552 |
14 | 25d1507c41a43 |
15 | 10d4aadb1aca6 |
hex | 7cfc884e221b |
137424060424731 has 16 divisors (see below), whose sum is σ = 190047509856288. Its totient is φ = 88257357504000.
The previous prime is 137424060424669. The next prime is 137424060424757.
It is a happy number.
137424060424731 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 137424060424731 - 27 = 137424060424603 is a prime.
It is a super-2 number, since 2×1374240604247312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (137424060425731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6128971950 + ... + 6128994371.
It is an arithmetic number, because the mean of its divisors is an integer number (11877969366018).
Almost surely, 2137424060424731 is an apocalyptic number.
137424060424731 is a deficient number, since it is larger than the sum of its proper divisors (52623449431557).
137424060424731 is a wasteful number, since it uses less digits than its factorization.
137424060424731 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12257966462.
The product of its (nonzero) digits is 2709504, while the sum is 48.
The spelling of 137424060424731 in words is "one hundred thirty-seven trillion, four hundred twenty-four billion, sixty million, four hundred twenty-four thousand, seven hundred thirty-one".
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