Base | Representation |
---|---|
bin | 11001100110010101… |
… | …10001100110001101 |
3 | 1022110210120020211202 |
4 | 30303022301212031 |
5 | 211121300130433 |
6 | 10151423555245 |
7 | 664400446025 |
oct | 146312614615 |
9 | 38423506752 |
10 | 13743364493 |
11 | 5912853181 |
12 | 27b675bb25 |
13 | 13b03b5151 |
14 | 945390a85 |
15 | 55683cee8 |
hex | 3332b198d |
13743364493 has 2 divisors, whose sum is σ = 13743364494. Its totient is φ = 13743364492.
The previous prime is 13743364457. The next prime is 13743364559. The reversal of 13743364493 is 39446334731.
13743364493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10519168969 + 3224195524 = 102563^2 + 56782^2 .
It is a cyclic number.
It is not a de Polignac number, because 13743364493 - 26 = 13743364429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13743364403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6871682246 + 6871682247.
It is an arithmetic number, because the mean of its divisors is an integer number (6871682247).
Almost surely, 213743364493 is an apocalyptic number.
It is an amenable number.
13743364493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13743364493 is an equidigital number, since it uses as much as digits as its factorization.
13743364493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1959552, while the sum is 47.
The spelling of 13743364493 in words is "thirteen billion, seven hundred forty-three million, three hundred sixty-four thousand, four hundred ninety-three".
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