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1375015250013 = 3458338416671
BaseRepresentation
bin10100000000100101010…
…010111010100001011101
311212110011011202222202020
4110000211102322201131
5140012012401000023
62531401232450353
7201225105532236
oct24004522724135
94773134688666
101375015250013
11490160297889
121a25a19a99b9
139c8815aca42
144a7a02b208d
1525b799a0de3
hex140254ba85d

1375015250013 has 4 divisors (see below), whose sum is σ = 1833353666688. Its totient is φ = 916676833340.

The previous prime is 1375015249943. The next prime is 1375015250033. The reversal of 1375015250013 is 3100525105731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1375015250013 - 29 = 1375015249501 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1375015250033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229169208333 + ... + 229169208338.

It is an arithmetic number, because the mean of its divisors is an integer number (458338416672).

Almost surely, 21375015250013 is an apocalyptic number.

It is an amenable number.

1375015250013 is a deficient number, since it is larger than the sum of its proper divisors (458338416675).

1375015250013 is an equidigital number, since it uses as much as digits as its factorization.

1375015250013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 458338416674.

The product of its (nonzero) digits is 15750, while the sum is 33.

The spelling of 1375015250013 in words is "one trillion, three hundred seventy-five billion, fifteen million, two hundred fifty thousand, thirteen".

Divisors: 1 3 458338416671 1375015250013