Base | Representation |
---|---|
bin | 10100000010110011101… |
… | …100111101001011111101 |
3 | 11212200022200110111002221 |
4 | 110002303230331023331 |
5 | 140031411014110331 |
6 | 2532434301245341 |
7 | 201341236400515 |
oct | 24026354751375 |
9 | 4780280414087 |
10 | 1377404441341 |
11 | 491176997675 |
12 | 1a2b49b63851 |
13 | 9cb72582a16 |
14 | 4a94971a845 |
15 | 25c695de711 |
hex | 140b3b3d2fd |
1377404441341 has 4 divisors (see below), whose sum is σ = 1385099438400. Its totient is φ = 1369709444284.
The previous prime is 1377404441291. The next prime is 1377404441359. The reversal of 1377404441341 is 1431444047731.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1377404441341 - 27 = 1377404441213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1377404441041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3847498261 + ... + 3847498618.
It is an arithmetic number, because the mean of its divisors is an integer number (346274859600).
Almost surely, 21377404441341 is an apocalyptic number.
It is an amenable number.
1377404441341 is a deficient number, since it is larger than the sum of its proper divisors (7694997059).
1377404441341 is an equidigital number, since it uses as much as digits as its factorization.
1377404441341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7694997058.
The product of its (nonzero) digits is 451584, while the sum is 43.
The spelling of 1377404441341 in words is "one trillion, three hundred seventy-seven billion, four hundred four million, four hundred forty-one thousand, three hundred forty-one".
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